Answer:
789
.5 is a 5 or larger so the 8 goes to a 9
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
Answer:
The explicit form for the sequence is: 
Step-by-step explanation:
In order to find an explicit form for the given sequence, you have to use the definition of arithmetic sequence and the <em>explicit formula</em>.
An arithmetic sequence is defined as a sequence where the difference of two consecutive terms is a constant.
The <em>explicit formula </em>is:
Where a1 is the first term, d is the common difference and an is the nth term of the sequence.
You have to subtract two consecutive terms to obtain d:
24-13= 11
35-24=11
Therefore d=11
In this case a1=13
Replacing in the formula:
Answer:
edfdv
Step-by-step explanation:
bfdbfgbn okay its 35
A critical point is just where a graph's slope is = to 0, so you can take the derivative of that function and set it equal to 0.
Using the chain rule:
f'(x) = 5(x-10)^4
0 = 5(x-10)^4
divide by 5 on both sides and take the 4th root of both sides.
0 = x - 10
add ten on both sides, and x = 10. Now, plug the x-value back into the original (you want to find the y-value on the original function ,not the derivative).
y = (10-10)^5 = 0
(10,0)
