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Vadim26 [7]
3 years ago
15

How do you add fractions?

Mathematics
1 answer:
Kay [80]3 years ago
5 0
The denominators have to be the same , if they're not then you can make them the same using a common denominator
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788.53 expressed to the neareast whole number​
boyakko [2]

Answer:

789

.5 is a 5 or larger so the 8 goes to a 9

Step-by-step explanation:

8 0
3 years ago
What are the zeros of the polynomial function?
Genrish500 [490]

Hello from MrBillDoesMath!

Answer:

x = 2 and 10


Discussion:

Approach 1:

20 = (-10)*(-2) and  (-10) + (-2) = -12 the coefficients of the polynomial. Hence

x^2 -12x + 20 = ( x- 2) * ( x-10)


Approach 2:

From the quadratic formula ( a = 1, b = -12, c = 20)

x =    (  -(-12) +\- sqrt( ((-12)^2 - 4*1*20) )  /  (2 * 1)

   =    ( 12 +\- sqrt( 144-80)  ) /2

  =   (12 +\-  sqrt(64) ) /2

  =  (12 +\- 8 ) /2


x  = ( 12 + 8) /2 = 20/2 = 10

or

x = ( 12 - 8)/ 2 = 4/2 = 2



Thank you,

MrB

5 0
3 years ago
Read 2 more answers
Consider the arithmetic sequence 13, 24, 35, ....
MArishka [77]

Answer:

The explicit form for the sequence is: a_{n}=13+(n-1)(11)

Step-by-step explanation:

In order to find an explicit form for the given sequence, you have to use the definition of arithmetic sequence and the <em>explicit formula</em>.

An arithmetic sequence is defined as a sequence where the difference of two consecutive terms is a constant.

The <em>explicit formula </em>is:

a_{n}=a_{1} + (n-1)d

Where a1 is the first term, d is the common difference and an is the nth term of the sequence.

You have to subtract two consecutive terms to obtain d:

24-13= 11

35-24=11

Therefore d=11

In this case a1=13

Replacing in the formula:

a_{n}=13+(n-1)(11)

8 0
3 years ago
W/5=w-14/9 this is a proprtion​
masya89 [10]

Answer:

edfdv

Step-by-step explanation:

bfdbfgbn okay its 35

8 0
3 years ago
Read 2 more answers
Determine all critical points for the function. f(x)=(x-10)^5
nikdorinn [45]
A critical point is just where a graph's slope is = to 0, so you can take the derivative of that function and set it equal to 0.

Using the chain rule:
f'(x) = 5(x-10)^4
0 = 5(x-10)^4

divide by 5 on both sides and take the 4th root of both sides.

0 = x - 10

add ten on both sides, and x = 10. Now, plug the x-value back into the original (you want to find the y-value on the original function ,not the derivative).

y = (10-10)^5 = 0

(10,0)
7 0
3 years ago
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