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3 years ago

When constructing an inscribed regular hexagon, what steps come after six arcs are created on the circle?

Mathematics

2 answers:

Mama L [17]3 years ago

3 0

Answer:

Connect every other intersection of an arc and the circle with a segment ⇒ 1st answer

Step-by-step explanation:

* Lets revise the steps of constructing an inscribed regular hexagon

1. Put your compass pin on the paper and draw a circle

2. Put a dot, labeled P, anywhere on the circumference of the

circle as a starting point.

3. Without changing the open of the compass, place the compass pin

on P and draw a small arc crossing the circumference of the circle.

4. Without changing the open of the compass, move the compass

pin to the intersection of the previous arc and the circumference

and draw another small arc on the circumference of the circle.

5. Repeat this step of until you return to point P.

6. Starting at P connect to adjacent arcs on the circle to form

the regular hexagon

- From these steps

∵ The step after six arcs are created on the circle is join the two

consecutive arcs by a segments

∴ Connect every other intersection of an arc and the circle with a

segment is the answer

Marrrta [24]3 years ago

3 0

Answer:

The answer is C

Connect every intersection of an arc and the circle with a segment.

Step-by-step explanation:

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3 years ago

How do i do this ?i need help on finding the answer . To all three questions

Igoryamba

Answer:

area of larger circle : 9π = 28.27

area of smaller circle: 4π = 12.57

area of shaded region: 15.71

Step-by-step explanation:

area of a circle = πr^2

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3 years ago

Tommy is using a bucket to collect nuts from a nut tree. He then dumps the bucket into a barrel for shipping of the nuts. He not

NISA [10]

Answer:

3/8 bucket

Step-by-step explanation:

Given that 1/4 bucket of nuts fills 2/3 of the barrel

PART A

To find the amount of nuts that fills entire basket we can put this as:

1/4 bucket → 2/3 barrel
x bucket → 1 barrel

Use cross-multiplication to find the value of x:

x×2/3 = 1×1/4
x = 1/4 ÷ 2/3
x = 1/4×3/2
x = 3/8 bucket

PART B

Using the bucket to barrel ratio to solve the problem. Having the number of required buckets as x and considering full barrel as 1 helps to find the value of x.

6 0

3 years ago

The door to my classroom is 84 inches tall. How many blocks would I need to stack to the height of the door, If each block is 2

nata0808 [166]

Answer:

42 blocks

Step-by-step explanation:

If each block is 2 inches, and the height of the door is 84 inches, you need to divide the height by the block size. Once you divide 84 by 2, you should get 42 blocks as your answer.

4 0

3 years ago

1. Approximate the given quantity using a Taylor polynomial with n3.

Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

$f(x) = x^{1/4}$

The n-th order Taylor polynomial for function f with its center at a is:

$p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}$

As n = 3 So,

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}$

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}$

$p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} } (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} + (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}$

$p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} } (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} + (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}$

$p_{3} (x)$ = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6

(0.0000018522752) (x-81)³

$p_{3} (x)$ = 0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

(x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

$p_{3} (94)$ = 0.0092592593 (94) - 0.000042866941 (94 - 81)² +

0.00000030871254 (94-81)³ + 2.25

= 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +

2.25

= 0.87037 03742 - 0.000042866941 (169) +

0.00000030871254(2197) + 2.25

= 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

$p_{3} (94)$ = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute $\sqrt[4]{94}$ as $94^{1/4}$ using calculator

Exact value:

$E_{a}$ (94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94) = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94) = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94) = 0.0001

4 0

3 years ago