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3 years ago

11

The sign of the product of 2 integers with the same sign is positive. what is the sign of the product of 3 integers with the sam

e sign

1 answer:

klemol [59]3 years ago

6 0

Product of 3 negatives equals a negative answer
Product of 3 positives equals a positive answer

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What is the value of p in the equation below?

stepladder [879]

Answer:

p = 8

Step-by-step explanation:

3x2 x 2x4 = px6

6 × 8 = 6p

48 = 6p

p = 48/6

p = 8

hope it helps!

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3 years ago

Winter math packet

stealth61 [152]

Answer:

32. C

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36. 2

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2 years ago

Read 2 more answers

PLEASE HELP! doing a test!

quester [9]

D is the correct answer to the equation.

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2 years ago

Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

Dovator [93]

The equation of the elipse is given by:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

$x_0 = \frac{27 + 1}{2} = 14$

$y_0 = \frac{0 + 0}{2} = 0$

$a = \frac{27 - 1}{2} = 13$

$a^2 = 169$

It has eccentricity of $\frac{5}{13}$ , thus:

$\frac{5}{13} = \frac{c}{a}$

$\frac{5}{13} = \frac{c}{13}$

$c = 13$

Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

$b^2 = a^2 - c^2$

$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

The equation of the elipse is:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

A similar problem is given at brainly.com/question/21405803

3 0

3 years ago

It’s a math question, plz help

olga2289 [7]

The answer to your question is D

8 0

3 years ago