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3 years ago

Find the greatest common factor for the list of terms X^5, x^6, x^8

Mathematics

1 answer:

Gnesinka [82]3 years ago

5 0

Answer:the GCF of the following terms x^5,x^6,x^8 is x^5

Step-by-step explanation:

x^5=x^5

x^6=x^5•x

x^8=x^5•x^3

x^5 is common to the three terms, therefore the GCF of the terms is x^5.

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slega [8]

Answer:

Step-by-step explanation:

If we think about a right triangle, we get that the hypotenuse is 24ft or the length of the ladder. The base of the ladder is 15ft away from the building which is the leg of the right triangle. The screenshot is the diagram (my drawing isn't that good lol:))

Thus we can use cosine function with the angle between the ladder and the ground since we need to find the angle and we get

$cos\alpha = \frac{15}{24}$

and $\alpha = 51.3 degrees$

The angle is 51.3 degrees hope that helps!

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2 years ago

A few years ago, when the fuel tank in Sally’s car was completely empty, she paid $63 to fill the tank with 22.5 gallons of gaso

Aloiza [94]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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grin007 [14]

Step-by-step explanation:

f(x) = (3/2)ˣ

g(x) = (2/3)ˣ

These are examples of exponential equations:

y = a bˣ

If b > 1, the equation is exponential growth.

If 0 < b < 1, the equation is exponential decay.

So f(x) is an example of exponential growth, and g(x) is an example of exponential decay.

Also, 2/3 is the inverse of 3/2, so:

g(x) = (3/2)^(-x)

So more specifically, f(x) and g(x) are reflections of each other across the y-axis.

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3 years ago

What operation does the Product Rule use

kumpel [21]

Answer:

addition

Step-by-step explanation:

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2 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$

$X - 35000 = -1.88*7000$

$X = 21840$

The designed life should be of 21,840 vehicle miles.

3 0

2 years ago