Question

A species of fly has two alleles for the length of their legs. The allele for long

Answer 1

Answer:

0.88

Explanation: First know the genotype frequency according to Hardy Weinberg equilibrium which is:

p= homozygous dominance, q= homozygous recessive and 2pq= heterozygous dominance, since the species carries both.

so you want to equate the equation following this respectively,

in our case p ²+q²+2pq=1

we have the value for q which is 12÷100=0.12

to get the value for P= 1- 0.12=0.88.

so your answer is 0.88 based on this equation.

Answer 2

Answer:

0.65

Explanation:

Remember to note the Hardy Weinberg equation of population in equilibrium;

p² + 2pq + q² = 1

q² = 12/100 = 0.12

q = 0.35

Then using the equation that; p + q = 1

p = 1 – q = 1 – 0.35 = 0.65