4 years ago

Solve the following equation, and check your solution. Be sure to show all work

Mathematics

1 answer:

fgiga [73]4 years ago

7 0

24 - 3x = -27

therefore -3x = -27-24

-3x = -51
-x= -17
therefore x is 17

You might be interested in

Factorise: <br> X(squared)-9

Gwar [14]

(x+3)(x-3)

−

)

(

)

Explanation:

−

is a

difference of squares

and in general

7 0

3 years ago

Read 2 more answers

Felicia tried to graph the point (5,1) on the coordinate plan at the right

nataly862011 [7]

Answer: She actually graphed it at (5,0) instead of (5,1)

Step-by-step explanation:

It should be one unit higher

4 0

3 years ago

What do both the Senate and the House of Representatives require of people running for election?

ludmilkaskok [199]

To be apart of that state for atleast ten years is one.

5 0

3 years ago

Read 2 more answers

Reduce the rational expression to lowest terms. If it is already in lowest terms, enter the expression in the answerbox. Also, s

givi [52]

Factorize both quadratic polynomials, as shown below

$\begin{gathered} a^2-3a-4=0 \\ \Rightarrow a=\frac{3\pm\sqrt{9+16}}{2}=\frac{3\pm\sqrt{25}}{2}=\frac{3\pm5}{2}\Rightarrow a=-1,4 \\ \Rightarrow a^2-3a-4=(a+1)(a-4) \\ \end{gathered}$

Similarly,

$\begin{gathered} a^2+5a+4=0 \\ \Rightarrow a=\frac{-5\pm\sqrt{25-16}}{2}=\frac{-5\pm3}{2}\Rightarrow a=-1,-4 \\ \Rightarrow a^2+5a+4=(a+1)(a+4) \end{gathered}$

Thus,

$\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{(a+1)(a-4)}{(a+1)(a+4)}$

Therefore, since the denominator cannot be equal to zero.

<h2>The variable restrictions for the original expression are a≠-1,-4</h2>

Then, provided that a is different than -1,

$\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{x-4}{x+4}$ <h2>The rational expression in the lowest terms is (x-4)/(x+4)</h2>

7 0

2 years ago

What's the volume of a cylinder if with a height of 8yd and radius 10.5yd

Pavlova-9 [17]

Answer:

V=πr2h=π·9. 2·7.32≈2118.49337m³

v=2118.49337m³

Step-by-step explanation:

5 0

3 years ago