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kvv77 [185]
3 years ago
12

Which of the following equations does not represent a true statement?

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

0-6-(3-)=3,

-6+(-3)=2 these two are wrong

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Rewrite the following integral in spherical coordinates.​
lora16 [44]

In cylindrical coordinates, we have r^2=x^2+y^2, so that

z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}

correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)

which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

4 0
2 years ago
The radius of a sphere and of a cylinder are the same. The diameter of the sphere and the height of the cylinder are also the sa
emmasim [6.3K]
First we have to know the formula of the volume f each of the solids, 

<span>V of sphere = 4/3 pi r^3
</span><span>Volume of Cylinder = pi r^2(2r)=2pi r^3
</span><span>Volume of cone = 1/3 pi r^2(r)=1/3 pi r^3
</span>
The surest and easiest way we can answer this is actually assigning values. We first assign values to r hence we would get the volume of the sphere and rest of the solids (cylinder and cone). You then compare your answers to that of the sphere, and you should get your answer. 
4 0
3 years ago
2. True False 6(10 + 5) - 6.10 + 6.5<br><img src="https://tex.z-dn.net/?f=10%20%2B%205%20-%206.10%20%2B%206.5%20%5Ctimes%206" id
Ostrovityanka [42]

Answer:

<h2>47.9</h2>

Step-by-step explanation:

10 + 5 - 6.10 + 6.5 \times 6 \\

Follow PEDMAS

10 + 5 - 6.10 + 39

15 - 6.10 + 39 \\ 15 + 39 - 6.10 \\ 54 - 6.10 \\  = 47.9

8 0
3 years ago
Read 2 more answers
If RV=w and SU=w–30, what is the value of w?
DIA [1.3K]

Answer:

w = 60

Step-by-step explanation:

the midsegment SU is half the measure of side RV, then

SU =  RV , so

w - 30 =  w ( multiply through by 2 to clear the fraction )

2w - 60 = w ( subtract w from both sides )

w - 60 = 0 ( add 60 to both sides )

w = 60

5 0
2 years ago
Solve.<br><br> Round to the nearest hundredth.<br><br> 29.3 = 1.7y
Elena-2011 [213]

Steps to Solve:

29.3 = 1.7y

29.3/1.7 = 1.7y/1.7

y = 17.2352941176

In this case, we round up the hundredths place because the number in the thousandths place is 5 or higher.

y = 17.24

Hope this helps!! :)

7 0
3 years ago
Read 2 more answers
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