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cricket20 [7]
3 years ago
10

How do you do this? I'm so confused

Mathematics
2 answers:
leonid [27]3 years ago
8 0
You could download photomath and it will tell you the answer
zepelin [54]3 years ago
7 0
There are lots of videos on YouTube on how to do it I’m not completely sure so I don’t want to tell you something false
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Find the product. (3p – 7)(3p + 7)
hram777 [196]
(3p - 7)(3p + 7) =
(3p × 3p) + (3p × 7) + (-7 × 3p) + (-7 × 7) =
9p^2 + 21p - 21p - 49
= 9p^2 - 49

Therefore, answer would be D.
8 0
3 years ago
Read 2 more answers
What is the volume of the figure​
Law Incorporation [45]

Answer:

5,376in^3

Step-by-step explanation:

find the volume of the smaller box first

10×4×12 = 480in^3

find volume of bigger box

17×12×24 = 4,896in^3

add both volumes 4,896 +480 = 5,376in^3

3 0
3 years ago
Read 2 more answers
lily, safia and manjit have 24 marbles altogether. manjit has the same number of marbles as lily and safia together. lily has 5
densk [106]

Answer:

7

Step-by-step explanation:

M = (L + S)

24/2 = 12

12-5 =7

L:5

S:7

7+5 = 12 (Manjit)

12+12= 24

7 0
2 years ago
Read 2 more answers
Which is equivalent to 64^1/4?<br> 2^4√4<br> 4<br> 16<br> 16^4√4
zalisa [80]

Answer:

Step-by-step explanation:

64^1/4\\\\=\dfrac{64^{1}}{4}  \\\\=\dfrac{64}{4} \\\\=16\\\\Answer\  C

7 0
3 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
3 years ago
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