70,000,000+8,000,000+600,000+20,000+1,000+80+7 = 78,621,087
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
Answer:
what
Step-by-step explanation:
From Left side:
NOTE: sin²θ + cos²θ = 1
Left side = Right side <em>so proof is complete</em>
Answer:
B
Step-by-step explanation:
C is too little and D is too much
