You use the formula y=mx+b, therefore you have to isolate the y
First you subtract 3x to both sides.
3x - 5y = -35
-3x -3x
Then it would be
-5y = -3x -35
Then you divide -5 on both sides to isolate the y
-5y = -3x -35
/-5 /-5 /-5
Two negatives cancel out and make a positive so it would be
Y = 3/5x + 7
(:
Answer:
the answer for X is -6
Step-by-step explanation:
g(X)=5/2x -1 and g(X)= - 1
sub -16 on g(X)
-16=5/2x -1
-16+1 = 5/2x
-15 = 5/2x
divide both sides by 5/2
X= -6
Answer: -1.6 is not a possible r-value.
Step-by-step explanation:
R-values range from -1 to +1. Out of all these numbers, -1.6 does not belong. Hence, -1.6 is not a r-value.
The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
