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Anton [14]
3 years ago
15

can someone please answer this question for me with stood please? Also don't mind the weird doodle on the side..

Mathematics
1 answer:
brilliants [131]3 years ago
5 0
Whats number question is it?

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How do you write 78,621,087 in expanded notation and expanded form?
Inga [223]
70,000,000+8,000,000+600,000+20,000+1,000+80+7 = 78,621,087
4 0
3 years ago
A special type of password consists of 3 different letters of the alphabet, and the two different numbers, where each letter and
Phoenix [80]

Answer:

There can be 14,040,000 different passwords

Step-by-step explanation:

Number of permutations to order 3 letters and 2 numbers (total 5)

(AAANN, AANNA,AANAN,...)

= 5! / (3! 2!)

= 120 / (6*2)

= 10

For each permutation, the three distinct (English) letters can be arranged in

26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways

For each permutation, the two distinct digits can be arranged in

10!/(10-2)! = 10!/8! = 10*9 = 90 ways.

So the total number of distinct passwords is the product of all three permutations,

N = 10 * 15600 * 90 = 14,040,000

7 0
3 years ago
14570.7 to 3 significant figures​
NemiM [27]

Answer:

what

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
How much will Bob need to save each month if he wants to buy a $30,000 car with cash in 5 years? He can earn a nominal interest
NeX [460]

Answer:

B

Step-by-step explanation:

C is too little and D is too much

7 0
3 years ago
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