2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
2 - 2sin^2 x + 3sin x = 0
2sin^2 x - 3sin x - 2 = 0
Let sin x = m, then
2m^2 - 3m - 2 = 0
2m^2 + m - 4m - 2 = 0
m(2m + 1) - 2(2m + 1) = 0
(m - 2)(2m + 1) = 0
m = 2 or m = -1/2
Now, sin x = -1/2
Therefore, x = 1/6(12nπ - π) and 1/6(12nπ + 7π)
Answer:
divide
Step-by-step explanation:
divide the first one by the second that might help
Given:
The given statement are:
a. Eight less than the product of seven and x.
b. The sum of six and the product of three and d.
To find:
The expression for the given statements.
Solution:
a.
Product of 7 and x is 7×x = 7x.
Eight less than the product of seven and x is 7x - 8.
Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.
b.
Product of 3 and d is 3×d = 3d.
The sum of six and the product of three and d is 6+3d.
Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.
Answer:
Step-by-step explanation:
(simplify)
(Add 3 to both sides)
(simplify)
(Multiply both sides by p)
(Multiply both sides by 2)
(Divide both sides by 7)
