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Alex_Xolod [135]
3 years ago
8

elliot counts a group of coims starting with rhe quarters his sister counts tje same coins.she starts counting the pennies.will

they get the same amont?explain
Mathematics
2 answers:
Vinvika [58]3 years ago
6 0
No because quarters are much bigger than pennies but there still in the same amount but they will not get the same amount : hope it helps
Leona [35]3 years ago
5 0
Yes because they are counting the same group
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The standard form of the equation of a circle is (x−3)^2+(y−1)^2=16.
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So the answer is A.......

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The sets D and J are given below.
sveta [45]
D n J = {7,8} (intersection)

Values that satisfy both sets.

D u J = {-1,1,4,5,7,8} (union)

All values present in both sets.
3 0
3 years ago
Lindsay is checking out books at the library, and she is primarily interested in mysteries and nonfiction. She has narrowed her
Ratling [72]

Answer:

0.0677 = 6.77% probability that they will all be nonfiction

Step-by-step explanation:

The books are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

10 + 12 = 22 books.

She chooses 4 books, which means that n = 4

12 nonfiction, which meas that k = 12

What’s the probability that they will all be nonfiction?

This is P(X = 4). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,22,4,12) = \frac{C_{12,4}*C_{10,0}}{C_{22,4}} = 0.0677

0.0677 = 6.77% probability that they will all be nonfiction

7 0
2 years ago
Which statements are correct? Check all that apply. One-halfQP = UT One-halfTS = RQ SU = PR SU âÂÄ„ RP UT ⊥ RP.
Alik [6]

Only option 1 and 4 are true.

Points S, U, and T are the midpoints of the sides of ΔPQR.

ΔSUT is inside of ΔPQR. Points S, U, and T are the midpoints of ΔPQR.

Which statements are correct? Check all that apply.

1.   QP = UT

2.   One-halfTS = RQ

3.   SU = PR

4.   SU ∥ RP

5.   UT ⊥ RP

Given to us,

S, U, and T are the midpoints of the sides of ΔPQR.

Using Triangle Midpoint Theorem, which states that the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.

Therefore, only option 1 and 4 are true.

To know more visit:

brainly.com/question/8943202

6 0
2 years ago
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