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Alex_Xolod [135]

4 years ago

8

elliot counts a group of coims starting with rhe quarters his sister counts tje same coins.she starts counting the pennies.will

they get the same amont?explain

2 answers:

Vinvika [58]4 years ago

6 0

No because quarters are much bigger than pennies but there still in the same amount but they will not get the same amount : hope it helps

Leona [35]4 years ago

5 0

Yes because they are counting the same group

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What’s 10x - 4 - 7/2x - 3/4(2x - 3) in its simplest form?

lyudmila [28]

10x-4-7/2x-3/4(2x-3)
6 1/2 -4 - 1 1/2x - 2 1/4
2 1/2- 1 1/2x- 2 1/4
1/4-1 1/2x
decimal form:
6.5-4-1.5x-2.25
2.5-1.5x-2.25
0.25-1.5x

7 0

3 years ago

-<br> 29<br> , -5.39, -<br> 27<br> 5<br> , -5<br> 7<br> 20

Korolek [52]

Are you wanting them in order?
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3 0

3 years ago

Read 2 more answers

The product of 3 consecutive odd numbers is 3,315. Enter a simplified expression for finding the numbers. Let n be the first odd

grin007 [14]

Answer:

$n^3+6n^2+8n=3315$

Step-by-step explanation:

Let n be the first odd number.

The 2nd consecutive odd number would be $n+2$ and 3rd consecutive odd number would be $n+2+2=n+4$ .

We have been given that the product of 3 consecutive odd numbers is 3,315. The product of 3 consecutive odd numbers would be $n(n+2)(n+4)$ .

Now we will equate the product with 3315 as:

$n(n+2)(n+4)=3315$

Let us simplify the left side of equation.

$(n\cdot n+n\cdot 2)(n+4)=3315$

$(n^2+2n)(n+4)=3315$

Now, we will apply FOIL to find the product of left side as:

$n^2\cdot n+n^2\cdot 4+2n\cdot n+2n\cdot4=3315$

$n^3+4n^2+2n^2+8n=3315$

$n^3+6n^2+8n=3315$

Therefore, our required equation would be $n^3+6n^2+8n=3315$ .

4 0

3 years ago

A representative of a market research firm contacts consumers by phone in order to conduct surveys. The specific consumer contac

Thepotemich [5.8K]

Answer: 0.421875

Step-by-step explanation:

According to the geometric distribution,

The probability that x number of trials take place until the first success occurs will be

$P(X=x)=(q)^{x-1}p$ , where p is the probability of getting success in each trial.

Given : The probability that a phone call produces a completed survey is p=0.25.

then q=1-0.25=0.75

Now, the probability that more than three phone calls are required to produce one completed survey :

$P(X>3)=1-P(X\leq3)\\\\=1-(P(1)+P(2)+P(3))\\\\=1-((0.75)^{1-1}(2.5)+(0.75)^{2-1}(2.5)+(0.75)^{3-1}(2.5))=0.421875$

Hence, the probability that more than three phone calls are required to produce one completed survey = 0.421875

3 0

3 years ago

Helppppppppp!!!!!!!

balandron [24]

Answer:

$= 2.06$

I hope I helped you^_^

3 0

3 years ago