Question

How do I solve for Log(x+3)+log2=3 ?

Answer 1

Answer:

he/she is correct

Answer 2

Answer: x = 995

Step-by-step explanation:

In this equation our log doesn't have a base so it is given the default base of 10. This makes our equation really.

$log_{10}(x+3) + log_{10}(2) = 3$

Now we put every equation as the exponent of our base 10 looks like this:

$10^{log_{10} (x+3)} + 10^{log_{10} (2)} = 10^{3}$

Now we cancel out the log base 10 and the 10. We are left with:

(x+3) + (2) = 10^3

Lastly solve for x

x + 5 = 1000

x = 995