we know that
p^2 is the the frequency of hba homozygote
we are given
frequency of hba homozygotes is 0.1
so,
p^2 =frequency of hba homozygotes
we can plug values
and we get
..............Answer
Answer:
There was a increase of 1.7% over these three years
Step-by-step explanation:
Multipliers:
For a decrease of a%, we multiply by: 
For a increase of a%, we multiply by: 
What was the percentage increase/decrease of groundhogs over these three years?
Decrease of 12%(multiplication by 0.88).
Increase of 6%(multiplication by 1.06).
Increase of 9%(multiplication by 1.09).
After these three years:
0.88*1.06*1.09 = 1.017
1.017 - 1 = 0.017
0.017*100% = 1.7%
There was a increase of 1.7% over these three years
Answer:
No solutions
Step-by-step explanation:
The slope is the same (3) The y-intercepts are different. Therefore, these are different parallel lines.
Please refer to the other post you saw.
Josh's estimate IS reasonable because when you have a number 5 or above after the decimal, you round up. Although it's reasonable to round up to 5 pounds, the actual amount is 4.5 pounds, or four and a half.