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2 years ago

What are all real roots of the equation 3x^3 - 18x^2 - 9x +132 = 0

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

6 0

Answer:

Read Below

Step-by-step explanation:

So, 3x^3 - 18x^2 - 9x + 132 = 0

The answer would be

Exact Form: 4, 1 + 2 \3, 1 - 2 \3

Decimal Form: 4,4.6410161...., -2.46410161

Hope this Helps :D

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Solve for zzz. 42=-7(z-3)42=−7(z−3)

xxTIMURxx [149]

Answer:

False

Step-by-step explanation:

Well to solve for z we single it out, distribute, use the communicative property, and combine like terms.

42 = -7(z - 3)42 = -7(z - 3)

Distribute

42 = -7z + 21*42 = -7z + 21

42 = -7z + 882 = -7z + 21

-42 to both sides

-7z + 840 = -7z + 21

-21 to both sides

-7z + 819 = -7z

+7z to both sides

819 = 0

<em>the given equation is false.</em>

<em>I hope this helps :)</em>

5 0

3 years ago

Dave collects U.S. gold coins. He has collection of 48 coins. Some are $10 coins, and the rest are $20 coins. If the face value

andrew11 [14]

Dave should slide some coins

7 0

2 years ago

Helpppppppppppppppp !!!!!!!!!!!!!!!

Bad White [126]

Answer:

Should be $160

<h3>Step-by-step explanation:</h3>

4 0

3 years ago

Read 2 more answers

X^2+5x=3x+11 solve by completing the square

goldenfox [79]

X^2+2x-11=0, this would be the answer that you are looking for m8.

7 0

3 years ago

Find the geometric means in the following sequence.

soldi70 [24.7K]

Answer:

Last choice. d.

Step-by-step explanation:

We are given the first term and the sixth term.

The first term is $a_1=-9$ .

The sixth them is $a_6=a_1r^5=-9216$ .

Let's solve for the common ratio, r.

$-9r^5=-9216$

Divide both sides by -9:

$r^5=1024$

Take the fifth root of both sides:

$r=1024^{\frac{1}{5}}$

$r=4$

So the common ratio is 4.

$a_1=-9$

$a_2=-9(4)=-36$

$a_3=-9(4)^2=-144$

$a_4=-9(4)^3=-576$

$a_5=-9(4)^4=-2304$

$a_6=-9(4)^5=-9216$

8 0

3 years ago