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Levart [38]
3 years ago
13

What is the x-coordinate of the point that divides the

Mathematics
1 answer:
fredd [130]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

In the picture attached, the problem is shown.

The formula you have to use is:

x = m/(m+n)(x2 - x1) + x1

where <em>x1</em> is the x-coordinate of the origin of the line segment (point J here), <em>x2</em> is the x-coordinate of the end of the line segment (point K here), and <em>m</em> and <em>n</em> are from the ratio m:n.

In this case:

  • x1 = -6
  • x2 = 8
  • ratio 2:5 means m = 2 and n = 5.

Replacing them into the equation, we get:

x = 2/(2+5)(8 - (-6)) + -6

x = -2

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x=5.38 . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.  picture is attached  . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x

By Pythagoras Theorem ,

Hypotenuse^2=Perpendicular^2+base^2

⇒ x^2=(3.6)^2+(4)^2

⇒ x=\sqrt{(3.6)^2+(4)^2}

⇒ x=\sqrt{12.96+16}

⇒ x=\sqrt{28.96}

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Therefore , x=5.38 . Correct option C)5.38

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Answer:

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Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

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Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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Answer:

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Step-by-step explanation:

The solution is the coordinates of the point (p,n) of intercept of lines described by given equations.

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