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Mathematics

1 answer:

Zinaida [17]2 years ago

6 0

Answer:

Please write out in english

Step-by-step explanation:

I cannot help unless you can translate.

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Write the equations of the following two sequences in "first term" form

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$\begin{array}{ccccccccccc}x&|&-2&|&\boxed0&|&1&|&3&|&6\\-&-&-&-&-&-&-&-&-&-&-\\y&|&1&|&\boxed3&|&4&|&2&|&0\end{array}\\.\\\\\boxed{f(0)=3}$

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If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?

Fittoniya [83]

Step 1: Find the value of one variable in terms of the other.

$a+3b=7\\a=7-3b$

Step 2: Substitute the value you just found for this variable in the other equation.

$3a-2b=8\\3(7-3b)-2b=8\\21-9b-2b=8\\21-11b=8\\21=8+11b\\13=11b\\\frac{13}{11}=b\\ b=1\frac{2}{11}$

Step 3: Use your new value for the second variable to find the first.

$a+3b=7\\a+3(1\frac{2}{11})=7\\a+3\frac{6}{11}=7\\\\a=3\frac{5}{11}$

Now that we know the values for a and b we can find the value of 4a+b.

$4a+b\\4(3\frac{5}{11})+1\frac{2}{11}\\12+\frac{20}{11}+1\frac{2}{11}\\\\12+1\frac{9}{11}+1\frac{2}{11}\\\\\boxed{15}$

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No links, downloads, or anything of the sort. I will give brainliest!!!

TiliK225 [7]

Answer:

The answer is D

Step-by-step explanation:

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