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Lyrx [107]
3 years ago
14

Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient

s? Explain your answer.
Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0

when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

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At a zoo, an Asian elephant is about 3 tons and eats about 300 pounds of food a day what percent of its body weight does the ele
olchik [2.2K]
3 Tons = 6000 pounds
300 is 5% of 6000 so the answer is 5% :)
8 0
3 years ago
A 4​-ft vertical post casts a 12​-in shadow at the same time a nearby cell phone tower casts a 118​-ft shadow. How tall is the c
stiv31 [10]

Answer:

height of vertical post = 6ft

its shadow = 20 in

For all shadows cast at the same time, the ratio of the height of a shadow-casting structure to the length of its shadow is the same. (Assuming, of course, that it's the sun casting the shadows.)

So the ratio is  

4 feet / 12 inches = 4 feet / 1 foot = 4/1 = 4,

and if h is the height of the cell tower,

h/122 feet = 4

h = 4 x 122 feet = 488 feet. <---------------- Final answer

Hope I helped,

-Adrian Velez

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h
stepan [7]

Answer:   c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

=0.539\times100=53.9\text{ cm}   [∵ 1 m = 100 cm]             (1)

The circumference of the ash tree= 0.509 yards

=0.509\times3\text{ feet}   [∵ 1 yard = 3 feet]

=0.509\times3\times 30.48\text{ cm}  [∵ 1 foot = 30.48 cm]

=46.54296\approx46.54\text{ cm}        (2)

The circumference of the elm tree = 6281.70 millimeters

=\dfrac{6281.70}{10}=628.17\text{ cm}          (3)

The circumference of the poplar tree = 0.000385 miles

=0.000385 \times5280\text{ feet}   [∵ 1 mile = 5280 feet]

=0.000385 \times5280\times30.48\text{ feet}  [∵ 1 foot = 30.48 cm]

=61.959744\approx61.96\ \text{ cm}              (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.

5 0
3 years ago
Let l be the length of a diagonal of a rectangle whose sides have lengths x and y, and assume that x and y vary with time. If x
meriva

The rate of change of the size of the diagonal is; 25.2 ft/s

By Pythagoras theorem;

The length, l of a diagonal of a rectangle whose sides have lengths x and y is;

  • l² = x² + y².

In essence; the length of the diagonal is dependent on the length, x and y of the sides.

Therefore;

(dl/dt)² = (dx/dt)² + (dy/dt)²

where;

  • (dx/dt) = 19 ft/s
  • (dy/dt) = -15 ft/s

Therefore,

(dl/dt)² = 19² + (-15)²

(dl/dt)² = 361 + 225

dl/dt = √586

dl/dt = 25.2

Therefore, the size of the diagonal is changing at a rate of; 25.2 ft/s.

Read more;

brainly.com/question/12559989

4 0
2 years ago
Step 2 - Fill in the missing number:<br> 2<br> 1 -3 -10 24<br> a<br> a =
Sunny_sXe [5.5K]

Answer:

16

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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