121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range
The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:
So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range
That's probably the answer they're looking for.
Answer:
$104,167 approx.
Step-by-step explanation:
Step one:
Given data
Morgan made $12,500 on the sale of a home.
Her commission she earns in selling homes is 12%
Step two:
let the cost of the home be x
So 12% of x= 12,500
12/100*x= 12,500
0.12*x=12,500
0.12x=12,500
divide both sides by 0.12
x= 12,500/0.12
x=$104,166.66
x=$104,167
Answer
-2.25 -13/5 1 3/5 -2.25
Step-by-step explanation:
The first one is true
<span>4(4a+10) is
</span>16 a + 40 after distribution
The second one is also true
<span>2(8a+20)
16a + 40 after distribution
Third is not true
</span><span>4a(4+10a)
</span><span>16a + 40a^2 after distribution
Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution
Hope this helps :)</span>
