<span>The higher the sum of the numbers 24 407 and 14 509 towards their difference?</span>
Answer:
Dom(gof)=Dom(f)={1,3,4}.
(gof)(1)=g{f(1)}=g(2)=3.
(gof)(3)=g{f(3)}=g(5)=1.
(gof)(4)=g{f(4)}=g(1)=3.
∴gof={(1,3),(3,1),(4,3)}.
(We know this from a=1/9 and r=3)
Simplifying this, we get:
Since we're finding the first term that exceeds 1000, let's set it equal to 1000.
Multiplying both sides by 27
n≈9.2
We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
=2187
Therefore the first term that exceeds 1000 is 2187, and it is the 10th term
Answer:
X = 8, Y = 8
Step-by-step explanation:
Step 1) Solve for Y w/ bottom equation to yield - y = -2/3x + 40/3.
Step 2) substitute equation into x + y = 16 to get 1/3x + 40/3 = 16 multiply by 3 to clear the fractions and get x + 40 = 48 - subtract 40 by both sides to get x = 8.
Step 3) Plug x = 8 into the bottom equation to get 48 + 9y = 120, subtract 48 by both sides to get 9y = 72 and then divide by 9. The product is y = 8.
the two triangles are congruent