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Tasya [4]
4 years ago
14

Please HELP me: 4x-3.75x=1.5x-1

Mathematics
2 answers:
Luden [163]4 years ago
8 0
4x-3,75x=1,5x-1\\\\
0,25x=1,5x-1\ \ \ |Subtract\ 1,5x\\\\
-1,25x=-1\ \ \ |Divide\ by\ -1,25\\\\x=0,8\\\\Solution\ is\ x=0,8.

cupoosta [38]4 years ago
7 0

Let's solve your equation step-by-step.<span><span><span>4x</span>−<span>3.75x</span></span>=<span><span>1.5x</span>−1</span></span>

<span><span /></span>Step 1: Simplify both sides of the equation.<span><span>0.25x</span>=<span><span>1.5x</span>−1</span></span>

<span><span /></span>Step 2: Subtract 1.5x from both sides.<span><span><span>0.25x</span>−<span>1.5x</span></span>=<span><span><span>1.5x</span>−1</span>−<span>1.5x</span></span></span><span><span>−<span>1.25x</span></span>=<span>−1</span></span>

Step 3: Divide both sides by -1.25.<span><span><span>‌<span><span>−<span>1.25x</span></span><span>−1.25</span></span></span>‌</span>=<span><span>‌<span><span>−1</span><span>−1.25</span></span></span>‌</span></span>

<span><span /></span><span><span>x=<span>0.8</span></span>
</span>

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The large and small intestine absorb water but the small intestine absorbs more water than the large intestine. Here the small intestine absorbs 9040 ml of water out of 9600ml while the large intestine absorbs the 560ml and 140ml leaves. To calculate percentage that was absorbed by the large intestine(percentage entering the small intestine) and also leaves, we divide the volume that leaves(140ml) by total volume absorbed(560ml) and multiply by 100.

Volume of water entering the small intestine= 9600 ml

Volume of water entering the large intestine= 560 ml

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Percentage of water entering the small intestine and absorbed by the small intestine= 9600ml - 560 ml= 9040

=9040/9600*100/1= 94.16%

Percentage of water entering the small intestine and absorbed by the volume leaving the large intestine = 560ml-140ml= 140/560*100/1= 25%

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There are 3 pieces with the number 2 on it, so there is a 3/6 chance of landing on it, simplifies that would be 1/2

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).

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