The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
brainly.com/question/4289712
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Simplify the equation.
First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7
Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7
Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6
Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12
Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6
Hope this helps.
22 students per class
88/4 = 22
Answer:
x = 14/9
Step-by-step explanation:
70 - 8x = 56 + x
- 8x - x = 56 - 70
- 9x = - 14
- x = - 14/9
x = 14/9
