Answer and explanation:
The large and small intestine absorb water but the small intestine absorbs more water than the large intestine. Here the small intestine absorbs 9040 ml of water out of 9600ml while the large intestine absorbs the 560ml and 140ml leaves. To calculate percentage that was absorbed by the large intestine(percentage entering the small intestine) and also leaves, we divide the volume that leaves(140ml) by total volume absorbed(560ml) and multiply by 100.
Volume of water entering the small intestine= 9600 ml
Volume of water entering the large intestine= 560 ml
Volume of water leaving the large intestine = 180 ml
Percentage of water entering the small intestine and absorbed by the small intestine= 9600ml - 560 ml= 9040
=9040/9600*100/1= 94.16%
Percentage of water entering the small intestine and absorbed by the volume leaving the large intestine = 560ml-140ml= 140/560*100/1= 25%
Also percentage of water absorbed by large intestine and doesn't leave the large intestine = 420/560*100/1= 75%
Answer:
Step-by-step explanation:
we have to find out the circumference of the pool
C=2*3.14*r
d=36, r=18
C=2*3.14*18=113.04 ft
Answer:
Yes
Step-by-step explanation:
Since the circle is split into 6 pieces, we can split the probability of landing on each section into fractions
There is one piece with the number 1 on it, so there is a 1/6 chance of landing on that.
There are 3 pieces with the number 2 on it, so there is a 3/6 chance of landing on it, simplifies that would be 1/2
There is one piece with the number 3 on it, so there is a 1/6 chance of landing on that.
There is one piece with the number 4 on it, so there is a 1/6 chance of landing on that.
Since the pieces with a 1 and 4 on the both have a 1/6 probabilit of landing, there is an equal chance on landing on either tile.
Answer:
The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence interval
, we have the following confidence interval of proportions.

In which
Z is the zscore that has a pvalue of
.
For this problem, we have that:
He takes a simple random sample of 122 people living in Gastown and finds that 25 have an annual income that is below the poverty line. This means that
and 
We have
, z is the value of Z that has a pvalue of
= 0.975, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).
Answer:
9x+4
Step-by-step explanation: