Question

A coin is tossed twice in succession. Let A be the event that the first toss is heads and let B the event that the second toss is heads. Find: (a) P(A) (b) P(B) (c) P(A∩B) (d) P(B /A)

Answer 1

Answer:

Step-by-step explanation:

A coin has two faces, a head (H) or tail (T). Tossing a coin twice in succession would give the following sample size;

                                 {HH, HT, TH, TT}

Given that: A = first toss is heads, B = second toss is heads, then:

i. P(A) = {HH, HT} = 2

ii. P(B) = {TH} = 1

iii. P(A∩B) = {HH} = 1

iv. P(B /A) = $\frac{1}{2}$