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3 years ago

Simplify using the Order of Operations.

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

first we'll have to do it in order which is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)

Step-by-step explanation:

(22÷2-2.5)+(4-6+6)

(11-2.5)+(4-6+6)

(8.5)+(4)

= 12.5

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A printer will produce 80 wedding invitations for $210. The price to produce 120 invitations is $290. The printer uses a linear

Vsevolod [243]

The answer is D)170.00

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4 years ago

What category of number does 14 fall into

BabaBlast [244]

Natural Numbers. {1, 2, 3, 4…..} These are also called Counting Numbers, and they're the numbers that can be used for counting.

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3 years ago

Hypothesis Testing

Yuri [45]

Answer:

Problem 1: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

Problem 1:

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, $H_A$ : p > 50% {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adult Americans who were worried about having enough saved for retirement = $\frac{156}{295}$ = 0.53

n = sample of adult Americans = 295

So, the test statistics = $\frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }$

= 1.03

The value of z-test statistics is 1.03.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.03) = 1 - P(Z $\leq$ 1.03)

= 1 - 0.8485 = 0.1515

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2:

We are given that a random sample of 35 trading days in 2014 resulted in a sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let $\mu$ = mean daily volume in Google stock

So, Null Hypothesis, $H_0$ : $\mu$ = 5.44 million shares {means that the volume of Google stock has not changed}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 5.44 million shares {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean volume in Google stock = 3.28 million shares

s = sample standard deviation = 1.68 million shares

n = sample of trading days = 35

So, the test statistics = $\frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }$ ~ $t_3_4$

= -7.606

The value of t-test statistics is -7.606.

Also, the P-value of the test statistics is given by;

P-value = P( $t_3_4$ < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

8 0

3 years ago

Find at least three different sequences beginning with the terms 3, 5, 7 whose terms are generated by a simple for- mula or rule

pychu [463]

1. Perhaps the simplest rule is one that makes this the start of an arithmetic sequence:

$a_{n+1}=a_{n}+2$

Then the sequence will continue ...

... 3, 5, 7, 9, 11, 13, 15, ...

2. We can multiply the two terms by some values, add the results, then add some constant. There are an infinite number of ways to choose such values. Here's one set of numbers that give the third term from the first two:

$a_{n+2}=4a_n-a_{n+1}$

Then the sequence will continue ...

... 3, 5, 7, 13, 15, 37, 23, ...

3. We can multiply adjacent values and add a constant.

$a_{n+2}=a_{n+1}\cdot a_n-8$

Then the sequence will continue ...

... 3, 5, 7, 28, 188, 5256, 988120, ...

5 0

3 years ago

Can you solve this problem? Don't forget to show your work :) thanks!

Rzqust [24]

Well, start from 100% and work backwards.

It takes 5600 years to get to 50%
Another 5600 years to get to 25%
And a bit under another 5600 to get to 15% (another 5600 years would get it down to 12.5%)

Add the first two 550s to get 1120, and add about 5,000 and see which answer is closest.
In this case, D is closest at 15!w29

There are more exact ways of solving, but for a multiple choice this is faster and efficient nonetheless

7 0

3 years ago