Answer:
12 and 6
Step-by-step explanation:
3x4 is 12
2x3 is 6
Answer: a. 242.5 pounds
b. 236 pounds
c . 208 and 278 pounds
The results are unlikely to be representative of all players in that sport's league because players randomly selected from championship sports team not the whole league.
Step-by-step explanation:
Given : Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team.
278 303 186 292 276 205 208 236 278 198 208
Mean = 
For median , first arrange weights in order
186, 198 , 205 , 208, 208 , 236 , 276 , 278 ,278, 292 , 303
Since , number of data values is 11 (odd)
So Median = Middlemost value = 236 pounds
Mode = Most repeated value= 208 and 278
The results are unlikely to be representative of all players in that sport's league because players randomly selected from championship sports team not the whole league.
9514 1404 393
Answer:
3 < x < 6
Step-by-step explanation:
Use the perimeter formula to write an expression for the perimeter. Then put that in an inequality with the given limits. Solve for x.
P = 2(L +W)
P = 2((4x) +(2x +1)) = 2(6x +1) = 12x +2 . . . . . fill in the given values; simplify
The perimeter wants to be between 38 and 74 cm, so we have ...
38 < 12x +2 < 74
36 < 12x < 72 . . . . . subtract 2
3 < x < 6 . . . . . . . . . divide by 6
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<em>Additional comment</em>
Solving a compound inequality is very much like solving a single inequality. You need to "undo" what is done to the variable. The rules of equality (ordering) still apply. If you were to multiply or divide by a negative number, the direction (sense) of the inequality symbols would reverse in the same way they do for a single inequality.
Here, our first step was to subtract 2 from all parts of the inequality:
38 -2 < 12x +2 -2 < 74 -2 ⇒ 36 < 12x < 72
The division by 12 worked the same way: all parts are divided by 12.
36/12 < (12x)/12 < 72/12 ⇒ 3 < x < 6
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If it makes you more comfortable, you can treat the perimeter limits as two separate inequalities: 38 < 12x+2 and 12x+2 < 74. Both restrictions apply, so the solution set is the intersection of the solution sets of these separate inequalities.
