Answer:
Step-by-step explanation:
because -3 is a zero, so x=-3
(k-1)(-3)²+k(-3)+1=0
9(k-1)-3k+1=0
9k-9-3k+1=0
6k=8
3k=4
k=4/3
(B)
∵ x=-1 is a zero of p(x)=kx²-4x+k
so k(-1)²-4(-1)+(-1)=0
k+4-1=0
k=-3
What grade are you in I mite have the picture of the answer

so the 2nd equation is really the first equation in disguise.
since both equations are the same, that means if you graph them, is just one line pancaked over the other, and the solutions points is every single one on each, namely
infinitely many solutions.
X1= 6-square root of 31
X2= 3
X3= 6+square root of 31