Answer:
x=2
Step-by-step explanation:
The diagram is attached below
TU=TW+WU
x+7=3+WU
WU=x+7-3
WU=x+4
To determine the value of x, we apply the theorem of intersecting chords.
TW X WU = CW X WV

A prime number is a natural number greater than 1 that can't be the factory of multiplying two smaller natural numbers.
The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057
9514 1404 393
Answer:
24m^14
Step-by-step explanation:
It looks like you want to simplify ...

__
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
(ab)^c = (a^c)(b^c)