Answer:
ln(5/3)
Step-by-step explanation:
The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.
<h3>Limit</h3>
We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

Answer:
Please check the explanation.
Step-by-step explanation:
Finding Domain:
We know that the domain of a function is the set of input or argument values for which the function is real and defined.
From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.
And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.
Thus, the domain is:
D: {-2, -1, 0, 1} or D: −2 ≤ x ≤ 1
Finding Range:
We also know that the range of a function is the set of values of the dependent variable for which a function is defined
From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.
And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.
Thus, the range is:
R: {0, 1, 2} or R: 0 ≤ y ≤ 2
Answer:
1. ∠A and ∠B are right angles. Given
2. m∠A = m∠ B All right angles are congruent.
3. ∠BEC≅ ∠AED Vertical angles are congruent
4. ΔCBE ~ ΔDAE AA
Step-by-step explanation:
A proof always begins with the givens.
1. ∠A and ∠B are right angles. -------------->Given
2. m∠A = m∠ B are equal since-----------> All right angles are congruent.
3. ∠BEC≅ ∠AED are also equal since---->Vertical angles are congruent
4. ΔCBE ~ ΔDAE since two angles are equal----------> AA
Answer:
-1/3
Step-by-step explanation:
if we use the rise over run method we see a fall of 1 and a run of 3. since we are using fall instead of rise that makes this slope negative. hope this helped :)
The degree is 3.
This video explains it pretty well: https://virtualnerd.com/pre-algebra/polynomials-nonlinear-functions/polynomials/monomial-polynomial-degrees/polynomial-degree-definition