Answer:
Step-by-step explanation:
Thank you! For letting me know
For every value tht x increases, y decreases by 3
-3x
Then to find the y intercept, look at 0's corresponding value (8)
-3x+8
line segment connecting the vertices of a hyperbola is called the <u>transverse axis</u> and the midpoint of the line segment is the <u>center</u> of the hyperbola.
What is transverse axis and center of hyperbola ?
The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.
And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.
Learn more about the transverse axis and center of hyperbola here:
brainly.com/question/28049753
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Answer:
See attached
Step-by-step explanation:
Table filled in, see picture
- The first column contains points with coordinates (x, y)
- The second column contains the rule (x + (-4), y + 2)
- The third column is obtained by applying the rule. Showing this for one of the vertices:
- Q: (1, 4)
- Apply rule: (1 + (-4), 4 + 2) = (1 - 4, 6) = (-3, 6)
- Get coordinates of Q' from previous step: (-3, 6)
So you get Q'(-3, 6) from Q(-1, 4) by applying the rule (x + (-4), y + 2).
Same steps for other vertices done and shown in the table.
Hope it is more clear.
