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Komok [63]
3 years ago
8

Question 1. Which of the following is not true for the equation six times d equals twelve?

Mathematics
1 answer:
Deffense [45]3 years ago
8 0
Q1. The answer is To solve, you must divide both sides by 6

The equation is:   6d = 12
<span>Multiplication is the inverse operation: TRUE -         6d = 12      d = 12/6
Checking the solution involves multiplication: TRUE -    6 * 2 = 12
The equation represents the number that gives twelve when multiplied by 6: TRUE     d is </span>the number that gives twelve when multiplied by 6<span>
To solve, you must divide both sides by 6: false


Q2. The answer is 18
</span><span>
x - the number of students

The students were divided equally among 3 chaperones: 3 chaperones per x
Each chaperone supervised 6 students: 1 chaperone per 6 students
 
3 : x = 1 : 6
x = 3 * 6 : 1
x = 18


Q3. The answer is </span><span>t is greater than or equal to five.
</span>
It will take Harlon at least five years to complete his college degree. The key word is at least. This means that it can include number 5 as well. He may need 5 years, 6 years, 7 years,... Hence, t is greater than or equal to five.


Q4. The answer is <span>1.2
</span>
<span>p over zero point three + 2 = 6
p/0.3 + 2 = 6

multiply both sides by 0.03
p + 2 * 0.3 = 6 * 0.3
p + 0.6 = 1.8
p = 1.8 - 0.6
p = 1.2


Q5. The answer is 2.

</span><span>16w = 32

Divide both sides by 16
16w/16 = 32/16
w = 2</span>
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Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop
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Answer:

The value of the test statistic is z = 1.78

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

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Sample 2:

\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Distribution of the difference:

X = \mu_1 - \mu_2 = 110 - 108 = 2

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What is the value of the test statistic?

z = \frac{X - \mu}{s}

z = \frac{2 - 0}{1.1226}

z = 1.78

The value of the test statistic is z = 1.78

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