Answer:
The correct option is 3. "At pH 6.5 the enyzme is 50% active"
Explanation:
For the titratable group to be protonated and cause the enzyme to be in the active state, it needs to have gained a hydrogen cation (H+). In order for that to happen, there must be enough hydrogen cations in the environment of the enzyme, and hence, an acidic pH is required in this case.
After two half-lives or 60 years, 7.5 g of the element will be left.
<u>Explanation:</u>
<u>Half-life:</u>
- In simple words, Half-life can be defined as the amount of time needed for a quantity to fall to half its value as contained at the beginning of the time period.
- In this problem the half-life of the element is thirty years, then after thirty years half of the sample would have decayed and half would be left as it is.
- After thirty years (The first half-life ) 30 /2 = 15 g declines and 15 g remains disappeared.
- And after another sixty years (The two half-lives) 15 /2 = 7.5 g declines and 7.5 g remains disappeared.
- After two half-lives or 60 years, 7.5 g of the element will be left.
Three
different ways the relatedness of species could be assessed is through:
<span>1.
</span>Their genotype. Similarity in DNA between the species is a good
indication of their relatedness.
<span>2.
</span>Their phenotype. If the two species have similar body form and function,
then there is a good possibility that they are related.
<span>The presence of intermediates, either living
or in the fossil record, can show relatedness between two species.</span>
Answer:
It can reduce carbon in the atmosphere.
The answer is
frequency of the homozygous recessive genotype --> q^2
frequency of the heterozygous recessive genotype --> 2pq
frequency of the recessive allele --> q
frequency of the dominant allele --> p
frequency of the homozygous dominant genotype --> p^2
Hope this will help for all
