Answer:
I believe C. greater abundance of commercial species is your answer. hope this helps and have a nice day!
Answer: Vacuole
Answer choices:
<span>Cell membrane
Mitochondrion
Nucleus
Vacuole</span>
Vacuoles<span> are membrane-bound structures found in both animal and plant cells. </span>
They have three important functions in plants -- provide support or rigidity, a storage for nutrients and waste matter until it can be removed, and decompose complex molecules.
Answer: B. The population using long sticks has mostly long sticks in its environment
Explanation:
Going back to the statement that reiterates the hypothesis after observations about the apes in the Introduction.
Reviewing the findings in this case, on the behavior of using sticks to dig seem to be the focus the experiment and choice length of the stick.
Making a judgment about whether or not the two finding has been supported is next step.
If there are equal numbers of short and long sticks in the environment of each population and the apes chooses one specific we can say their behavior is learned.
If the chimpanzees using short sticks have made the the sticks short by breaking long sticks then we can say this behavior is learned.
When the Young chimpanzees in both populations start out using sticks of many different sizes we can see that these variables of learning is yet to be perfected.
When individuals in the population that don’t use the common stick length for that population catch fewer termites this reveals a randomness in the behavior of interest.
At this point we can say that if the population using long sticks has mostly long sticks in its environment then there is a biased objective in the study and this does not support the hypothesis that the choice of stick length is a learned behavior.
Answer:
The correct answer will be option-C.
Explanation:
The process of translation in prokaryotes is complex process and proceeds in three steps: initiation, elongation and termination.
1. Ribosomal subunits: 50S (5S and 23S subunit) and 30S (16S and proteins).
2. Initiation factors: IF1, IF-2 and IF-3 which help in the formation of assembly.
3 GTP: guanosine triphosphate as a source of energy.
4. Charged tRNA: with N-formylmethionine is the first amino acid.
5. mRNA: the RNA to be translated.
Since the option contains both 50S and 16S components of ribosome thus, Option-C is the correct answer.
Answer: Hello your question has some missing data attached below is the missing data
answer : single spots for “b”, “sn”, and “y” ( option C )
Explanation:
During the mitotic crossing over in a heterozygous individual the phenotypes that could result are single spots for “b”, “sn”, and “y” . this is because In mitosis/mitotic crossing there is no pairing up and no swapping of chromosomal segments Hence no variations are introduced during mitosis /mitotic crossing
