Answer:
y = -2x+11
Step-by-step explanation:
If we have a slope and a line, we can use the slope intercept form of a line
y-y1 = m(x-x1)
where (x1,y1) is the point and m is the slope.
Substitute in what we know
y-5 = -2 (x-3)
We want it in slope intercept form which is y = mx+b
Distribute the -2
y-5 = -2x+6
Add 5 to each side
y-5+5 = -2x +11
Cant really see it................
Answer:
Please check the explanation.
Step-by-step explanation:
Given
a)
f(x) + g(x) = (2x - 1) + (2 - x)
= 2x -1 + 2 - x
= x + 1
b)
f(x) - g(x) = (2x - 1) - (2 - x)
= 2x - 1 - 2 + x
= 3x - 3
c)
g(-5) - f(-5)
Putting x = -5 in g(x) = 2 - x
g(x) = 2 - x
g(-5) = 2 - (-5) = 2+5 = 7
Putting x = -5 in f(x) = 2x - 1
f(x) = 2x - 1
f(-5) = 2(-5) - 1
= -10 - 1
= -11
Thus,
g(-5) - f(-5) = 7 - (-11) = 7+11 = 18
d)
f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2
e)
f(g(x)) = f(2-x)
= 2(2-x)-1
= 4-2x-1
= 3-2x
