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rusak2 [61]
3 years ago
15

Please help me... :(

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

6

Step-by-step explanation:

Think of it as a ratio. The recipe calls for 2:3. If Jason used 4, then you need to match the other side.

4/2=2

So you need to multiply 3 by 2 to find the match.

3x2=6

The ratio is 4:6, so Jason uses 6 teaspoons of baking powder.

-hope it helps

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The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The
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Answer:

34% of lightbulb replacement requests numbering between 47 and 52

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 52

Standard deviation = 5

Between 47 and 52:

52 is the mean and 47 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean.

Since the normal distribution is symmetric, of those, 34% are within 1 standard deviation below the mean and the mean(47 and 52) and 34% are within the mean and one standard deviation above the mean(52 and 57).

So

34% of lightbulb replacement requests numbering between 47 and 52

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3 years ago
Which is defined using the undefined terms point and line?
jeka94

Answer:

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Step-by-step explanation:

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4 years ago
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The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

can be wrtten as:

\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

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