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4 years ago

Helpppppppp pleaseeeeee

Mathematics

2 answers:

Gekata [30.6K]4 years ago

5 0

Answer:

negative

Step-by-step explanation:

okay so look at the rise and the run of this line (that is given). slope is defined as rise divided by run. the "rise" is the change in y values, while the "run" is the change in x values. the rise in this problem is -4, as shown on the graph. the run is 3, as also shown there. therefore, the slope is -4/3. the type of slope this is is negative slope because the slope is clearly negative.

Novosadov [1.4K]4 years ago

5 0

Answer:

-4/3

Step-by-step explanation:

(-1 - 3)/(1 - -2)

use the slope formula (y2 - y1)/(x2 - x1)

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Which statement describes the behavior of the function f(x)=3x/4-x?

Oksana_A [137]

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

$f(x)=\frac{3x}{4-x}$

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}$

Taking x common from the denominator.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}$

Cancel out common factor x.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3}{\frac{4}{x}-1}$

Apply limits.

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}$

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}$

$\lim_{x\rightarrow \infty}f(x)=-3$

Therefore the graph approaches –3 as x approaches infinity.

7 0

4 years ago

Read 2 more answers

Examination, 152 Candidates offered Agriculture

agasfer [191]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the given details

$n(G)=136,n(P)=128,n(A)=152,n(A\cap G)=52,n(A\cap P)=60,n(A\cap P\cap G)=30,n(P\cap G)=58$

STEP 2: Get the number of students that takes the subjects only

From the basic stuff, we have Number of candidates who had taken only each of the subjects

$\begin{gathered} n(A\text{ only)=}n(A)-\lbrack n(A\cap P)+n(A\cap G)-n(A\cap P\cap G)_{}\rbrack \\ \Rightarrow152-\lbrack52+60-30\rbrack=152-82=70 \\ \\ n(G\text{ only)=}n(G)-\lbrack n(A\cap G)+n(P\cap G)-n(A\cap P\cap G)\rbrack \\ \Rightarrow136-\lbrack52+58-30\rbrack=56 \\ \\ n(P\text{ only)=}128-\lbrack58+60-30\rbrack=40 \end{gathered}$

STEP 3: Represent the values above on a Venn Diagram after getting the values

STEP 4: Find the total number of candidate that sat for the exam.

$\begin{gathered} We\text{ su}m\text{ all the numbers in the Venn diagram to get the total number of candidates that sat for the exam} \\ We\text{ have:} \\ 70+22+30+30+28+56+40=276 \end{gathered}$

Hence, the total number of candidates that sat for the exam is 276