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yan [13]
3 years ago
9

15. Find the length of segment DE of the triangle ABC.

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

Option C. 26\ units

Step-by-step explanation:

we know that

Triangles ADE and ABC are similar by AA similarity postulate

AB=2AD

Apply proportion

\frac{AD}{AB}=\frac{8x-6}{12x+4}\\ \\\frac{AD}{2AD}=\frac{8x-6}{12x+4}\\ \\\frac{1}{2}=\frac{8x-6}{12x+4}\\ \\12x+4=16x-12\\ \\16x-12x=4+12\\ \\4x=16\\ \\x=4\ units

Find the length of segment DE

DE=8x-6=8(4)-6=26\ units

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Answer:

The required answer is (201)_4-(32)_4=(103)_4.

Step-by-step explanation:

Consider the provided numbers:

We need to subtract in base 4.

(201)_4-(32)_4

The place value of 201 is:

1 is at units place, 0 is at four's place and 2 is at 4 squared place.

The place value of 32 is:

2 is at units place and 3 is at four's place.

201

- 32

Start subtracting the numbers from the unit place.

Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.

Also change 0 to 4 because we have borrow 4 from squared place.

Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.

Now the number will look like this:

135

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Now subtract the number as shown.

135

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103

Hence, the required answer is (201)_4-(32)_4=(103)_4.

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3 years ago
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Answer:

Step-by-step explanation:

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