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coldgirl [10]
3 years ago
8

Ursula bought 9 dozen rolls of first aid tape for the health office.The rolls were divided equally into 4 boxes.How many rolls a

re in each box
Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

there is 27 rolls in each box. please mark me brainliest:)

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Please do this for me and I will give you brainliest and everything PLEASE...
Vikki [24]

Answer: 156.25

Step-by-step explanation:

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3 years ago
How many sixes are equal to double 27?
Phantasy [73]

Answer:

its not sixes theres 4 sixes equal 24 so there is no answer

Step-by-step explanation:

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2 years ago
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Write 31/11 as a decimal. If necessary, use a bar to indicate with digit or group of digits repeats
Andrews [41]

Answer:

2.81

Step-by-step explanation:

.81 has a bar over it.

5 0
3 years ago
I need the answer pleaseee​
Aleksandr [31]

Answer:

y= -3x + 150

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7 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
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