So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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Answer is 2 (answer choice a)
<span>(-45 + (-12) / 2 = -28.5
</span>So the answer is -28.5
Answer:
32.5
Step-by-step explanation:
% over 100 = is/ of
50% over 100 = x / 65
cross multiply
3250/ 100x = 32.5
Answer: -3
mark me brainiest very easy answer
