For this case we must find an expression equivalent to:
Then, we take common factor 8:
By definition of power properties we have to:
So:
Since both terms are perfect cubes, we factor using the cube difference formula:
Where:
So:
Answer:
students in art class make square tiles that are 5 inches long. they plan to make a row of tiles that is 4 feet 2 inches long.ho
2 answers:
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Given:
The length of the rectangle = 16 ft
The width of the rectangle = 12 ft
The diameter of the semicircle = 12 ft
To find the area of the given figure.
Formula
where,
be the area of the given figure
be the area of the rectangle
be the area of the semicircle.
- The area of the rectangle =
where, l be the length and b be the width
- Area of the semicircle =
, r be the radius of the semicircle.
Now,
The radius of the semicircle r = 6 ft
Putting, r=6, l=16 and b= 12 we get,
sq ft
or, sq ft
sq ft
or, sq ft
So,
sq ft
= 248.52 sq ft
Rounding off to the nearest tenth, we get;
A=248.5 sq ft.
Hence,
The area of the composite figure is 248.5 sq ft.
