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Contact [7]
3 years ago
11

Trigonometry Trigonometric Equations cos x = √ 2/2;x [ 0,2π]

Mathematics
2 answers:
koban [17]3 years ago
7 0
Here you go...................

shepuryov [24]3 years ago
5 0

Answer:

x = π/4, 7π/4

Step-by-step explanation:

cos x = √2/2

basic angle = π/4

x = π/4,

2π - π/4 = 7π/4

x = π/4, 7π/4

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PLZ HELP!!!!!!!!!!!!!!!!!!!!
amm1812
The answer will be C.
5 0
3 years ago
3X +112 equals 180 solve for X
photoshop1234 [79]

Answer:

22.6-This is a repeating decimal.  I just couldn't find the line for above the six.

Step-by-step explanation:

3x+112=180

3x=68

x=22.6-This is a repeating decimal.  I just couldn't find the line for above the six.

5 0
3 years ago
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
Pls help; I will mark brainliest!
anzhelika [568]

Answer:

20 inches

Step-by-step explanation:

15 =(3/4)x

15/(.75)=20

4 0
4 years ago
Read 2 more answers
Area of a triangle with verticals of (-4,1),(-7,5),(0,1)
Lynna [10]

Answer:

8 ft^2

Step-by-step explanation:

I assume that the three points given are the vertices of the triangle. So the three points are:

A (-4,1)

B (-7,5)

C (0,1)

The area of a triangle is given by:

A=\frac{1}{2}bh

where b is the base and h is the height.

Here we can take as follows:

- We can take the base to be the side AC, so that its length is equal to the distance between the two points:

AC=\sqrt{(0-(-4))^2+(1-1)^2}=4

- The height of the triangle is therefore the perpendicular distance between AC and point B. This is equivalent the difference in the x-coordinate between any point on AC and B, so:

h=(5-1)=4 ft

Therefore, the area of the triangle is:

A=\frac{1}{2}(4)(4)=8 ft^2

7 0
3 years ago
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