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3 years ago

What is the factored form of the difference of two squares.

Mathematics

1 answer:

V125BC [204]3 years ago

3 0

$a^{2} - b^{2} = (a+b) (a-b)
$
hope this helps.

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Spare an answer sir?

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yes

Step-by-step explanation:

3+ 9*4 = 3 + 36 = 39

39 is bigger than 15

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Examine the algebraic expression.

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The following list contains the number of movies that a group of 10 students saw in theaters in the past 12 months. 18, 15, 20,

tigry1 [53]

Place in ascending order: 4 6 8 15 15 17 17 18 20 20

middle numbers = 15 and 17

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2 years ago

Nikos sold muffins at his club's bake sale.he spent $28.50 on supplies. he sold his muffins for $0.75 each, and made a profit of

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Divide $0.75 by $36.75? Sorry if I'm wrong, mathematics isn't my best subject.

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3 years ago

Which equation is the inverse of y = 9x2 - 4?

m_a_m_a [10]

Answer:

The inverse will be:

$y' = \frac{\sqrt{x+4}}{3}$

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

$f(x) = 9x^{2} - 4$

$y = 9x^{2} - 4$

$x = 9y' ^{2} - 4$

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

$x + 4= 9y'^{2} - 4+4$

$9y'^{2}$ = x + 4

Second divide by 9

$9y'^{2}$ /9 = (x + 4)/9

$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

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3 years ago