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netineya [11]
4 years ago
7

27a⁰c³ for a =⅔, c = -⅓

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
6 0

Answer:

- 1

Step-by-step explanation:

Using the rules of exponents

a^{0} = 1

(a^n)^{m} = a^{nm}

Given

27a^{0}(-\frac{1}{3}) ^{3}

Note a^{0} = 1 for any value of a, thus

= 27 × 1 × - \frac{1}{3^{3} }

= 27 × 1 × - \frac{1}{27} ← cancel the 27 on numerator/ denominator

= 1 × - 1

= - 1

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Answer:

(2,1)

Step-by-step explanation:

3x+y = 7

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