Question

27a⁰c³ for a =⅔, c = -⅓

Answer 1

Answer:

- 1

Step-by-step explanation:

Using the rules of exponents

$a^{0}$ = 1

$(a^n)^{m}$ = $a^{nm}$

Given

27$a^{0}$$(-\frac{1}{3}) ^{3}$

Note $a^{0}$ = 1 for any value of a, thus

= 27 × 1 × - $\frac{1}{3^{3} }$

= 27 × 1 × - $\frac{1}{27}$ ← cancel the 27 on numerator/ denominator

= 1 × - 1

= - 1