Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

Answer 1

Answer:

y = (-3/2)x - 4

Step-by-step explanation:

If y = (2/3)x + 9, the slope is 2/3.  Any line perpendicular to this line would have the slope -3/2, which is the negative reciprocal of 2/3.

If the perpendicular line passes thru (-6, 5), then the equation in slope-intercept form would be:

y = mx + b, or (here) 5 = (-3/2)(-6) + b.  From this we see that b = -4, and the desired equation is y = (-3/2)x - 4 (Answer Choice #3)