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EastWind [94]
3 years ago
13

On January 1, 2016, Skyward Company purchased a copy machine. The machine costs $320,000, its estimated useful life is 8 years,

and its expected salvage value is $20,000. What is the depreciation expense for 2017 using double-declining-balance method
Business
1 answer:
never [62]3 years ago
3 0

Answer:

$60,000

Explanation:

Double declining method is a depreciation method used to expense the cost of an asset.

Depreciation expense using the double declining method = Depreciation factor × cost of asset

Deprecation factor = 2 (1/useful life) = 2(1/8) = 1/4

Depreciation expense in 2016 = 0.25 × $320,000 = $80,000

Net book value = $320,000, - $80,000 = $240,000

Deprecation expense in 2017 = 0.25 x $240,000 = $60,000

I hope my answer helps you

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Vera_Pavlovna [14]

Answer:

E

Explanation:

In this question, we are to give an answer about which of the listed options would give George the optimal service for the action which he seeks to execute.

Checking the requirements of what he is trying to do, we will notice that there are some key words that are very important that he is trying to target. Now, to bring his idea into fruition, Google AdWords would provide him with the needed help.

This is because Google AdWords would look specifically at indexes using those two key words he wants to use to provide him with the results that he seeks.

5 0
3 years ago
Read 2 more answers
A fleet of refrigerated delivery trucks is acquired on January 5, 2017, at a cost of $900,000 with an estimated useful life of 1
gavmur [86]

Answer:

depreciation expense 2017 = $180,000

depreciation expense 2018 = $144,000

depreciation expense 2019 = $115,200

Explanation:

purchase cost $900,000

estimated useful life 10 years

depreciation expense using double declining method = 2 x regular straight method depreciation rate x purchase cost

depreciation expense 2017 = 2 x 1/10 x $900,000 = $180,000

depreciation expense 2018 = 2 x 1/10 x $720,000 = $144,000

depreciation expense 2019 = 2 x 1/10 x $576,000 = $115,200

8 0
3 years ago
"'Suppose that while in college, you saved money by eating generic fruits and vegetables from the grocery store. Now, suppose th
zysi [14]

Answer:

Normal goods

Explanation:

Normal goods are goods that are goods whose demand increases when income increases and falls when income falls.

I increase my demand for organic fruits and vegetables when my income increased. This shows they are normal goods.

Generic fruits and vegetables are inferior goods.

Inferior goods are goods whose demand falls when income rises and increases when income falls.

I hope my answer helps you

8 0
3 years ago
QS 4-15 Computing and analyzing gross margin ratio LO A2 Carrier Lennox Trane York Sales $ 150,000 $ 550,000 $ 38,700 $ 255,700
kogti [31]

Answer:

Maybe is you payed attention you would have knew the answer

Explanation:

Good luck :))

4 0
2 years ago
Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,
wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is  = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time =  mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be I_i :

I_i = \dfrac{R^2}{\mu (\mu-R)}

I_i = \dfrac{2.1^2}{5 (5-2.1)}

I_i = \dfrac{4.41}{5 (2.9)}

I_i = \dfrac{4.41}{14.5}

\mathbf{I_i = 0.30}

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

\delta = \dfrac{R}{\mu}

\delta = \dfrac{2.1}{5}

{\delta = 0.42}

\mathbf{\delta = 42}

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - \delta

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58  × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0
3 years ago
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