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Firdavs [7]
3 years ago
13

____ allows you to control how objects enter, move on and exit slides

Computers and Technology
2 answers:
kkurt [141]3 years ago
6 0
The answer to this is custom animations. 
(Hope it helped ^_^)
Misha Larkins [42]3 years ago
4 0
The answer is power-point.<span />
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The following method public String removeFromString(String old, String frag) removes all occurences of the string frag from the
Mashutka [201]

private static String removeFromString(String old, String frag)

{

int i = old.indexOf(frag);

while (i> -1) {

String rest = old.substring(i + frag.length());

System.out.println("rest = " + rest);

old = old.substring(0, i);

System.out.println("rest = " + old);

old = old + rest;

System.out.println("rest = " + old);

i = old.indexOf(frag);

System.out.println("i = "+ i);

}

return old;

}

Here the index of first occurrence is obtained outside the “while loop” and if this loop runs until index value is >-1. It extracts the rest of the characters other than “frag” from the index and all the characters for which the given set of characters are removed.

4 0
3 years ago
It needs to be as simple as possible. Each question is slightly different.1. An arithmetic progression is a sequence of numbers
madam [21]

Answer

can we get a picture of the problem ?

Explanation:

4 0
3 years ago
16.
dimaraw [331]
  • Answer:

<em>r = 15 cm</em>

  • Explanation:

<em>formula</em>

<em>V = πr²×h/3</em>

<em>replace</em>

<em>4950 = 22/7×r²×21/3</em>

<em>4950 = 22/7×r²×7</em>

<em>4950 = 22×r²</em>

<em>r² = 4950/22</em>

<em>r² = 225</em>

<em>r = √225</em>

<em>r = √15²</em>

<em>r = 15 cm</em>

3 0
3 years ago
What is Dailymotion Cloud on the Dailymotion site?
lana [24]
C, a video solution that is adaptable to the users storage space
4 0
3 years ago
Read 2 more answers
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack
Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

  • In the first point, the max method is declared that compares the string and returns its max value.
  • In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.
7 0
3 years ago
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