Answer:
b. 2.9!
Explanation:
There are is a mistake in the question.
Suppose the group consist of 10 kids and 2 adults, the number of ways in which they can form the line is:
= 2! 10!
= 2× 1× 10!
= 2.10!
But since that is not in the given option.
Let assume that the group consists of 9 kids and 2 adults, the number of ways in which they can form the line is:
No of ways the kids can be permutated = 9 ways
No of ways the adult can be permutated = two ways.
Thus; the number of ways in which they can form the line = 2! 9!
= 2 × 1× 9!
= 2.9!
Stage Selected Values in the Sales Processes
Explanation:
A system administrator is the individual responsible for maintaining, configuring, and managing computer systems efficiently, particularly multi-user machines like servers.
Defining opportunities which comprise the selling process appropriately is one of the main functions for any company using Sales-force to monitor the performance of its sales process.
The Opportunity Stage Sales-force model off - the-box standards also reflect not the vocabulary or process that sales people use in the company As a result, Sales-force companies frequently make three main mistakes when describing their selling terminology.
Answer:
The answer is "Unstructured"
Explanation:
In comparison, unstructured information applies to information, which doesn't suit the conventional column and rows concerning databases properly. It is also known as sources, that include mails, audio and video files, web pages and posts in communication networks.
- This tracks and communicates on travel and object flow-through sensors and much more.
- These types of data are used in both companies and organizations.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
B. only accesible over the internet
