
let's notice, the squared variable is the "y", and therefore is a horizontal parabola, with a vertex as you see at 5,3.
the coefficient of the y² is positive, meaning it opens to right-hand-side.
the "p" distance is 2 units, since it's opening to the right, is positive 2.
so from the vertex at 5,3 we move to the right 2 units, to land at (7, 3).
Answer:
Maximize Z = 6x1 + 3x2
other answers are as follows in the explanation
Step-by-step explanation:
Employee Glass Needed per product(sq feet) Glass available per production
Product
Wood framed glass Aluminium framed glass
doug 6 0 36
linda 0 8 32
Bob 6 8 48
profit $300 $150
per batch
Z = 6x1 + 3x2,
with the constraint
6x1 ≤ 36 8x2 ≤ 32 6x1 + 8x2 ≤ 48
and x1 ≥ 0, x2 ≥ 0
Maximize Z = 6x1 + 3x2
to get the points of the boundary on the graph we say
when 6x1= 36
x1=6
when
8x2= 32
x2=4
to get the line of intersect , we go to
6x1 + 8x2 ≤ 48
so, 6x1 + 8x2 = 48
When X1=0
8x2=48
x2=6
when x2=0
x1=8
the optimal point can be seen on the graph as attached
Answer:
x=2187
Step-by-step explanation:
please mark this answer as brainlest