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marysya [2.9K]
3 years ago
7

. Write the following exponential expressions as equivalent radical expressions. a. 2^(1 /2)

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0

Answer:

So 2^{\frac{1}{2}} will be equivalent to \sqrt{2} in radical form

Step-by-step explanation:

We have given expression 2^{\frac{1}{2}}

We have to write this in radical form

We know that if any fraction is in exponential form then if we write this in radical form then in radical form the exponent come inverse of its number

So 2^{\frac{1}{2}} can be written in radical form as \sqrt{2}

So 2^{\frac{1}{2}} will be equivalent to \sqrt{2} in radical form

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Talja [164]

Answer:

A commercial fisherman is  

EQUALLY LIKLEY

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A person who smokes is  

MORE LIKLEY

to need health insurance than a nonsmoker.

An 18-year-old male college student is  

LESS LIKLEY

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5 0
3 years ago
if you had 75 bars of chocolate but you gave 60 away, what is the percentage of thw amount you gave away?
mars1129 [50]
Total chocolate bars: 75
Chocolate bars given away: 60

60/75 = 0.8 or 80%
7 0
3 years ago
Can someone help me
True [87]

Answer:

Why is this long?

Step-by-step explanation:

4 0
3 years ago
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Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hou
rewona [7]

Answer:

I will make <u>$ 13.20</u> per hour

Step-by-step explanation:

Given:

Employee gets money for Working from 2.00 PM to 6.00 PM = \$ 12 per hour

Employee gets money for working from 6.00 PM to 12.00 AM  will get additional 10\%=\frac{10}{100}\times12= \$ 1.2 per hour

Employee gets money for working from 12.00 AM to 01.00 AM will get additional 15\%=\frac{15}{100}\times12= \$ 1.8 per hour

Solution:

Employee works from 2.00 PM to 12.00 AM= Employee gets money for Working from 2.00 PM to 6.00 PM + 10\% extra wage = \$ 12 + \$ 1.2 = \$ 13.2

7 0
3 years ago
How long will it take for 2 g of a sample of iodine-131, which has a half-life of about 8 days, to decay to 0.04 g?
Zigmanuir [339]
We know that

<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A----------->  is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h------------->  is the half-life-----------> 8 days

for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
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ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days

the answer is 45.15 days
6 0
3 years ago
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