Question

What is the surface area of this triangular prism rounded to the nearest tenth?

Answer 1

The answer is C.
SA = bh + (s1 + s2 + s3)H
SA = (6.8)(5.1) + (6.8 + 5.1 + 8.5)(2.5) = 85.68

Answer 2

Answer:

The correct option is C.

$\text{The surface area is=}85.7cm^2$

Step-by-step explanation:

Given the right triangular prism.

we have to find the surface area of given right triangular prism.

As triangular prism is formed with two right triangles and 3 rectangles with different length and breadth.

∴ $\text{Surface area =}2(\frac{1}{2})base\times height + (s_1 + s_2 + s_3)H$

                                        $=(6.8)(5.1)+(6.8+ 5.1+8.5)(2.5)$

                                        $=85.68\sim85.7cm^2$

Hence, correct option is C.