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Anna71 [15]
3 years ago
7

The lenght of a rectangle is 4 centimeters less than twice its width. The perimeter of the rectangle is 34 cm .what are the dime

nsions of the rectangle?
Mathematics
1 answer:
kondaur [170]3 years ago
3 0

Answer:

Step-by-step explanation:

34=2(2w-4)+(2w)

34=4w-8+2w

34+8=6w

42=6w

w=42/6

w=7

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Identify which equations have one solution, infinitely many solutions, or no solution.
notsponge [240]
First one= x=5
second one= x=1/30 or 0.03 or 30^-1
third one= All real numbers or R
fourth one= No solution
Fifth one= All real numbers or R
Sixth one= p=-10/3 or -3 1/3 or -3.3

R is just the symbol for all real numbers. Also know as infinitely many solutions.

Hope this helps ! :) have a good day! Make sure you eat.
7 0
3 years ago
A rectangular box is 6 inches wide 10 inches long and 2 inches tall how much wrapping paper is needed to cover the box exactly
stepladder [879]

Answer:

184 in²

Step-by-step explanation:

Given :

Width, w = 6 inches

Length, l = 10 inches

Height, h = 2 inches

To obtain how much wrapping paper is needed ; we take the surface area of the box

Surface area = 2(lw + lh + wh)

Surface area = 2((6*10) + (6*2) + (10*2))

Surface area = 2(60 + 12 + 20)

Surface area = 2(92)

Surface area = 184 in²

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7 0
3 years ago
Ms Hart had 40 dollars to spend on costume boxes for the musical. If she bought 12 boxes and received 4 dollars in change, how m
artcher [175]

Answer:each box cost =$3

Step-by-step explanation:

Amount of money Ms Hart has to spent on costume boxes=$40

Amount gotten as change after purchase=$4

Amount actually used up buying costume boxes =$40-$4=36

Since she bought 12 boxes , each box cost =$36/ 12=$3

5 0
3 years ago
If f(x)= x^2+x and h(x)=5x-2 find f(f(2))
alexandr1967 [171]
<h3>Answer: 2f^2 </h3>

Step-by-step explanation:

Remove the parentheses: = ff x 2

Apply exponent rule: f^1+^1x2

Add the numbers 1+1=2 = 2f^2

I hope this is right.

7 0
3 years ago
BRAINLIEST!!! HELP!!<br><br> 15. Where is the circumcenter of a right isosceles triangle located?
drek231 [11]

Answer:

At the midpoint of the hypotenuse

Step-by-step explanation:

The circumcentre is the point of intersection of the 3 perpendicular bisectors.

It is positioned.

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Outside all Obtuse triangles.

At the midpoint of the hypotenuse on all Right triangles.

4 0
3 years ago
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