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sergij07 [2.7K]
3 years ago
12

How do you tell if a equation is linear or non linear

Mathematics
1 answer:
NARA [144]3 years ago
7 0
Linear means in a straight line, non linear n o line
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Find the equation of a line passing through points (-7, -10) , (-5, -20)
LuckyWell [14K]

You want to find the equation for a line that passes through the two points:

                          (-7,-10) and (-5,-20).

First of all, remember what the equation of a line is:

                                y = mx+b

here, m is the slope, b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through.

Consider (-7,-10) as point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-7 and y1=-10.

Consider (-5,-20), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=-20.

Now, just plug the numbers into the formula for m above, like this:

                       m= (-20 - -10)/(-5 - -7)

                                m= -10/2

                                   m=-5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

                                     y=-5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-7,-10). When x of the line is -7, y of the line must be -10.

(-5,-20). When x of the line is -5, y of the line must be -20.

Because  line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-5x+b. b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specifically passes through the two points (-7,-10) and (-5,-20).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.


You can use either (x,y) point you want.The answer will be the same:

(-7,-10). y=mx+b or -10=-5 × -7+b, or solving for b: b=-10-(-5)(-7). b=-45.

(-5,-20). y=mx+b or -20=-5 × -5+b, or solving for b: b=-20-(-5)(-5). b=-45.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-7,-10) and (-5,-20) is y=-5x-45.

                                 


8 0
3 years ago
-117/7 divide and simplify
kifflom [539]
117/7 already is in the simplest form. It can be written as 16.714286 in decimal form (rounded to 6 decimal places).
8 0
3 years ago
an auto transport truck holds 12 cars. A car dealer plans to bring in 1150 new cars in June and July. If an auto transport truck
marusya05 [52]

Answer: 96 truckloads, 95 will be full, the last on will have 10 cars


Step-by-step explanation:  1150/12= 95.888> 95*12=1140, 1140+10=1150


6 0
3 years ago
Hurry please!!!! Unit 4 congruent triangles
STatiana [176]

Answer:

I don't think u put up a picture

4 0
3 years ago
Read 2 more answers
(Need Answer!)
zalisa [80]

Answer:

k = 7

Step-by-step explanation:

Applying,

S = (y₂-y₁)/(x₂-x₁)................ Equation 1

Where S = slope of the line.

From the question,

Given: y₂ = 10, y₁ = 4, x₂ = k, x₁ = 1, S = 1

Substitute these values into equation 1

1 = (10-4)/(k-1)

crossmultiplying,

(k-1) = (10-4)

k-1 = 6

k = 6+1

k = 7

8 0
2 years ago
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