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alexandr1967 [171]
4 years ago
13

Write a function g whose graph represents the indicated transformation of the graph of f(x)=-2|x-4|+2​

Mathematics
1 answer:
labwork [276]4 years ago
4 0

Answer:

g(x) = -Ix - 4I + 1

Step-by-step explanation:

* Lets revise some transformation

- If the function f(x) translated horizontally to the right by h units, then

 the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left by h units, then

 the new function g(x) = f(x + h)

- If the function f(x) translated vertically up by k units, then the new

 function g(x) = f(x) + k

- If the function f(x) translated vertically down by k units, then the

 new function g(x) = f(x) – k

- A vertical stretching is the stretching of the graph away from the

 x-axis

- If k > 1, the graph of y = k • f(x) is the graph of f(x) vertically

 stretched by multiplying each of its y-coordinates by k.

- A vertical compression is the squeezing of the graph toward

 the x-axis.

- If 0 < k < 1 (a fraction), the graph of y = k • f(x) is the graph of f(x)

 vertically compressed by multiplying each of its y-coordinates by k.

- If k should be negative, the vertical stretch or compress is followed

 by a reflection across the x-axis.  

* Lets solve the problem

∵ The graph of f(x) represented by the function f(x) = -2Ix - 4I + 2

∵ The y-intercept of f(x) is -6 and y-intercept of g(x) is -3

∵ -3/-6 = 1/2

∴ We will multiply f(x) by 1/2 to get the y-intercept of g(x)

- That means f(x) is compressed vertically by scale factor 1/2 to be g(x)

∴ g(x) = 1/2 [ -2Ix - 4I + 2]

∴ g(x) = -Ix - 4I + 1

- To be sure from the answer check the point (4 , 2) in f(x), when

  we multiply the y-coordinate by 1/2 the point change to (4 , 1)

  which is belong to g(x) that means f(x) translate 1 unit down to be

  g(x)

∴ g(x) = -Ix - 4I + 1

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