The prime factor of the 576 is $2^6 * 3^2$ and the prime factor of the 64 is $2^6$ . And the expression $\sqrt{\dfrac{576}{64}}$ is equal to 3.

<h3>What is simplification?</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

The expression is $\sqrt{\dfrac{576}{64}}$

The prime factor of the 576 will be

$576 = 2^6 * 3^2$

The prime factor of the 64 will be

$64 = 2^6$

Then the expression will be

$\sqrt{\dfrac{576}{64}} = \sqrt{\dfrac{2^6 * 3^2}{2^6}}\\\\\sqrt{\dfrac{576}{64}} = \sqrt{3^2}\\\\\sqrt{\dfrac{576}{64}} = 3$

More about the simplification link is given below.

brainly.com/question/12616840

5 0

2 years ago

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>