Answer: X'(-3, -2), Y'(-5, 1), and Z'(2, -3)
Step-by-step explanation:
Upon reflection across the x-axis, the x-coordinates remain the same while the signs of the y-coordinates flip. So, the coordinates will be X(3, -2), Y(5, 1), and Z(-2, -3).
Upon reflection across the y-axis, the signs of the x-coordinates will flip while the signs of the y-coordinates remain the same. So, the coordinates will be X′(-3, -2), Y′(-5, 1), and Z′(2, -3).
Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / <span>8St^2
Rewriting the squared terms in simplified form :
</span>Width = 16 x S x S x t / <span>8 x S x t x t
</span>Cancelling the like terms
Width = 16 x S / <span>8 x t
</span>Cancelling the numeric terms :
Width = 2S / <span>t</span>
Answer:
C. y = log 1/6 x
Step-by-step explanation:
im literally on this right now on edge lol
Divide 2 by 5: 2/5=.4. Move the decimal two places to the right: .4=40%. The percent is 40% :)
Answer:
dV/dt = 100 cm³/min
Step-by-step explanation:
Given
V = 728 cm³
P = 182 kPa
dP/dt = - 25 kPa/min
dV/dt = ?
If we apply the ideal gas equation
P*V = n*R*T
where n*R*T is constant
we have
d(P*V)/dt = d(n*R*T)/dt
⇒ d(P*V)/dt = 0
⇒ V*(dP/dt) + P*(dV/dt) = 0
⇒ dV/dt = - (V/P)*(dP/dt)
Plugging the known values we obtain
⇒ dV/dt = - (728 cm³/182 kPa)*(- 25 kPa/min)
⇒ dV/dt = 100 cm³/min
